Students must choose one of the following terms for their research for Journal ArticleSummary:collaboration, divisional structure, functional structure, horizontal structure, matrix structure, outsourcing, re-engineering, teams, vertical linkages, or virtual team.InstructionsJournal Article Summary & Discussion: Within each module, there is a list of key terms. Each student will select one of the key terms and conduct a search of Campbellsville University’s online library resources to find 1 recent peer reviewed article (within the past 3 years) that closely relate to the concept. Your submission must include the following information in the following format:-DEFINITION: a brief definition of the key term followed by the APA reference for the term; this does not count in the word requirement.SUMMARY: Summarize the article in your own words-this should be in the 150-200-word range. Be sure to note the articles author, note their credentials and why we should put any weight behind his/her opinions, research or findings regarding the key term.DISCUSSION: Using 300-350 words, write a brief discussion, in your own words of how the article relates to the selected weekly reading assignment Key Term. A discussion is not rehashing what was already stated in the article, but the opportunity for you to add value by sharing your experiences, thoughts and opinions. This is the most important part of the assignment.REFERENCES: All references must be listed at the bottom of the submission–in APA format.Be sure to use the headers in your submission to ensure that all aspects of the assignment are completed as required.Any form of plagiarism, including cutting and pasting, will result in zero points for the entire assignmentDue Sunday of Week 2 by 11:55pm EST
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′ − 4y′ + 3y = x ; use y1 = e3x vi. y′′ + 5y′ + 6y = e2xcos(x) vii. y′′ + y = sec(x) tan(x)
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′