Select the Best SolutionConsider strong supporting evidence, pros, and cons. Is this solution realistic?Drafting the CaseOnce you have gathered the necessary information, a draft of your analysis should include these general sections, but these may differ depending on your assignment directions or your specific case study:IntroductionIdentify the key problems and issues in the case study.Formulate and include a thesis statement, summarizing the outcome of your analysis in 1–2 sentences.BackgroundSet the scene: background information, relevant facts, and the most important issues.Demonstrate that you have researched the problems in this case study.Evaluation of the CaseOutline the various pieces of the case study that you are focusing on.Evaluate these pieces by discussing what is working and what is not working.State why these parts of the case study are or are not working well.Proposed Solution/ChangesProvide specific and realistic solution(s) or changes needed.Explain why this solution was chosen.Support this solution with solid evidence, such as:Concepts from class (text readings, discussions, lectures)Outside researchPersonal experience (anecdotes)RecommendationsDetermine and discuss specific strategies for accomplishing the proposed solution.If applicable, recommend further action to resolve some of the issues.What should be done and who should do it?Finalizing the CaseAfter you have composed the first draft of your case study analysis, read through it to check for any gaps or inconsistencies in content or structure:Is your thesis statement clear and direct?Have you provided solid evidence?Is any component from the analysis missing?
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′ − 4y′ + 3y = x ; use y1 = e3x vi. y′′ + 5y′ + 6y = e2xcos(x) vii. y′′ + y = sec(x) tan(x)
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′