Reaction Paper 1This week your first reaction paper is due. Follow the guidelines and expectations given in Module 1.3.The reaction paper is due Sunday at 11:59 PM ET.Review the rubric herePlagiarismYou are expected to write primarily in your own voice, using paraphrase, summary, and synthesis techniques when integrating information from class and outside sources. Use an author’s exact words only when the language is especially vivid, unique, or needed for technical accuracy. Failure to do so may result in charges of Academic Dishonesty.Overusing an author’s exact words, such as including block quotations to meet word counts, may lead your readers to conclude that you lack appropriate comprehension of the subject matter or that you are neither an original thinker not a skillful writer.RubricPSY 3761 Reaction Paper RubricPSY 3761 Reaction Paper RubricCriteriaRatingsPtsThis criterion is linked to a learning outcomeLength Requirement: two pages long (acceptable if a bit longer).5.0 PtsFull CreditWas submitted to the drop box by Sunday at 11:59 p.m. ET in the week assigned.0.0 PtsNo Credit- 10% each day late up to 3 days5.0 ptsThis criterion is linked to a learning outcomePaper follows APA format in terms of margins, font, citing, referencing, quoting, etc.25.0 PtsFull CreditWas submitted to the drop box by Sunday at 11:59 p.m. ET in the week assigned.0.0 PtsNo Credit- 10% each day late up to 3 days25.0 ptsThis criterion is linked to a learning outcomeAccurate review and analysis of peer-reviewed journal article50.0 PtsFull CreditWas submitted to the drop box by Sunday at 11:59 p.m. ET in the week assigned.0.0 PtsNo Credit- 10% each day late up to 3 days50.0 ptsThis criterion is linked to a learning outcomeGrammar and spelling accuracy20.0 PtsFull CreditWas submitted to the drop box by Sunday at 11:59 p.m. ET in the week assigned.0.0 PtsNo Credit- 10% each day late up to 3 days20.0 pts
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′ − 4y′ + 3y = x ; use y1 = e3x vi. y′′ + 5y′ + 6y = e2xcos(x) vii. y′′ + y = sec(x) tan(x)
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′