Please Note: Using a minimum of 4 recent scholarly peered


  

Please Note: Using a minimum of 4 recent scholarly peered reviewed articles less than 5yrs old for DQ 1 and 2. Must be cited using APA format, 750 words for each topic AND include the HTTP or DOI for all references used.

 DQ 1

Should prisoners with a history of opiate dependence be offered opiate replacement therapy while incarcerated? Why or why not?

 DQ 2

What are the ethical considerations of prescribing psychotropic medications for psychotic individuals? What are the risks of inmates taking these medications? How can prison officials reduce these risks when it appears that an inmate could benefit from psychotropic medications? How might prison officials encourage an atmosphere of compliance with such a program?

PLEASE SEE RESOURCES:

1. Prisoners’ Experiences of Antipsychotic Medication: Influences on Adherence

Read “Prisoners’ Experiences of Antipsychotic Medication: Influences on Adherence” by Mills, Lathlean, Bressington, Forrester, Van Veenhuyzen, & Gray from Journal of Forensic Psychiatry & Psychology (2011). https://lopes.idm.oclc.org/login?url=http://search.ebscohost.com/login.aspx?direct=true&db=psyh&AN=2011-03587-008&site=ehost-live&scope=site

  

2. Correctional Mental Health: From Theory to Best Practice

Read Chapter 7 in Correctional Mental Health: From Theory to Best Practice.

View Resource

https://bibliu.com/app/#/view/books/9781452236315/epub/OEBPS/s9781544302805.i809.html#page_238

Share This Post

Email
WhatsApp
Facebook
Twitter
LinkedIn
Pinterest
Reddit

Order a Similar Paper and get 15% Discount on your First Order

Related Questions

Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′ − 4y′ + 3y = x ; use y1 = e3x vi. y′′ + 5y′ + 6y = e2xcos(x) vii. y′′ + y = sec(x) tan(x)

Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′