Physical Activity Resource BrochureAfter reading the websites cited in the Overview and your peer’s Discussion posts develop a one-page Physical Activity Resource Brochure/infographic. Imagine that your peers all live in the same general location. Research one fun and unusual but accessible activity that will meet the physical activity goals of you and your peers.Remember to search for activities on Living Social, Groupon, Department of Recreation and Parks brochures, club and meetings sections of the newspaper, bulletin boards in your favorite neighborhood coffee shop or grocery store, etc. Develop a one-page infographic as the brochure which offers information on:a description of the activitycostwhen and wherewebsite or copy of the listing locationThe activity should be described as above noted with the addition of photos or graphics to enhance the brochure. Pictures and graphics are required.You may submit your brochure/infographic in PowerPoint, PDF, Word or Microsoft Publisher format. View websites onhow to create an 8 X 11.5 color infographic (one-pageWord or pdf. document), but do not purchase formatting options.http://blog.hubspot.com/blog/tabid/6307/bid/34223/5-Infographics-to-Teach-You-How-to-Easily-Create-Infographics-in-PowerPoint-TEMPLATES.aspxhttp://blog.hubspot.com/marketing/free-ppt-infographic-templates-designs-htAssignment Expectations:Length: One-pageStructure: One-page colored infographic/brochureReferences: Use appropriate APA style in-text citations and references for all resources utilized to answer the questions. A minimum of two (2) scholarly sources are required for this assignment. Citations on infographic where used, references at the bottom of infographic.
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′ − 4y′ + 3y = x ; use y1 = e3x vi. y′′ + 5y′ + 6y = e2xcos(x) vii. y′′ + y = sec(x) tan(x)
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′