For this assignment, we will be putting together an annotated bibliography of at least 8 sources for a potential final project proposal. These sources can include the non-required reading section of the syllabus.However, academic articles from well-regarded journals and trusted journalistic sources are preferred, andwe encourage you to use your best judgment as scholars when selecting these sources.How will you know if the academic article is from a well-regarded journal? If in doubt, please see thisColorado State guide to evaluating the credibility of sources in a college paper. Don’t overthink this toomuch: if you have a burning question, post on Piazza, but otherwise, go with your intuition on the source.We’ll let you know if the source doesn’t meet our standards when we evaluate these.To complete this assignment, please do the following:1. Provide one paragraph introducing your topic. This paragraph must include your research questionand your preliminary thesis (1-3 sentences) that provide your early working answer to this question.2. Next, provide at least 8 sources on this topic area that you have read. For each of these sources, pleasedo the following:x88 Provide each source in a bibliographic citation format of your choice (MLA, Chicago, or any otherso long as you are consistent in your style).x88 Summarize the main argument or finding of the source in 1-3 sentences.x88 Provide your reflection on this piece, whether or not it has influenced your thinking on the subject,and whether or not it will make it into your proposal (in the literature review or as the framingpuzzle of your project, for example) in 1-3
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′ − 4y′ + 3y = x ; use y1 = e3x vi. y′′ + 5y′ + 6y = e2xcos(x) vii. y′′ + y = sec(x) tan(x)
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′