discussion question :After viewing After Darwin: Genetics, Eugenics, and the Human Genome and Its Time to Question Bio-engineering think about the issues and benefits that have come about from the technologies discussed. What do you believe are the greatest advancements or benefits discussed, and what or where do you feel is the greatest potential for risk or harm? Give examples directly from the film/films to illustrate your understanding.After viewing the required films for this module answer the following promptBe sure you have read all of the instructions and etiquette guidelines under the General Information section of this course.(please watch the list of the films and also use chapter 4 chapter 5 ppt s context to answer the question )need at least 300 words)Required Films(If the embedded film does not load you may need to log in to the college library to watch Films on Demand portal films. Follow the instructions in the General Course Information section if you do not know how)Paul Root Wolpe: Its time to question bio-engineeringEvolutionary Biology Essentials-Watch the segments Radio Carbon and Other Dating Techniques, Absolute Dating and Fossil Dating onlySuggested Viewing: These films are short 2 to 5 minute films to help illustrate some of the concepts being discussed.What is DNA?https://www.statedclearly.com/videos/what-is-dna/What is a gene?https://www.statedclearly.com/what-exactly-is-a-gene/Video Genotypes and Phenotypeshttps://www.youtube.com/watch?v=OaovnS7BAocVideo Evolution of populationshttps://www.youtube.com/watch?v=odWnb1GHPfIVideo Microevolution – Macroevolution (forces of evolution)https://www.youtube.com/watch?v=jeza0g3E8wE
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′ − 4y′ + 3y = x ; use y1 = e3x vi. y′′ + 5y′ + 6y = e2xcos(x) vii. y′′ + y = sec(x) tan(x)
Obtain the general solution of the following DEs: i. y′′′ + y′′ − 4y′ + 2y = 0 ii. y(4) + 4y(2) = 0 iii. x(x − 2)y′′ + 2(x − 1)y′ − 2y = 0; use y1 = (1 − x) iv. y′′ − 4y = sin2(x) v. y′′